Question

Sabendo que log 2 = 0,3 e log 3 = 0,47, calcule: log150 e log20

Answer 1

log150

log2.3.5^2

log2+log3+2log5

log2+log3+2log10/2

log2+log3+2(log10-log2)
0,3+0,47+2(1-0,3)
0,3+0,47+2(0,7)
0,77+1,4=2,17

log20

log2^2.5
2log2+log5

2log2+log10-log2

0,6+1-0,3
1,6-0,3=1,3