Question

sabendo que cossec X =13/5 e pi/2 <x< pi,calcule.

a)sen x
b)cos x
c) tg x
d) sec x​

Answer 1

senx= 1/cosecx = 5/13

cosx=√1-sen²x= √1-(25/169)= √144/169 = -12/13

tgx = senx/cosx = 5/13 / -12/13 = -5/12

secx = 1/cosx = -13/12