Question

sabendo que AB= 10 cm, calcule quanto mede AC:
me ajudem pfvrrrr​

Answer 1

resposta foto: 15/4

triangulos semelhantes (caso angulo angulo angulo)

Answer 2

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$\large\boxed{\begin{array}{l}\sf\overline{AC}+\overline{CB}=10\implies \overline{CB}=10-\overline{AC}\\\sf\dfrac{3}{5}=\dfrac{\overline{AC}}{\overline{CB}}\\\\\sf\dfrac{3}{5}=\dfrac{\overline{AC}}{10-\overline{AC}}\\\sf 5\overline{AC}=3\cdot(10-\overline{AC})\\\sf 5\overline{AC}=30-3\overline{AC}\\\sf 5\overline{AC}+3\overline{AC}=30\\\sf8\overline{AC}=30\\\sf \overline{AC}=\dfrac{30\div2}{8\div2}\\\sf\overline{AC}=\dfrac{15}{4}\\\sf \overline{AC}=3,75~cm\end{array}}$