sabendo que a soma das raizes da equaçao x²+(2k-3)x+2=0 e igual a 7
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b=( 2k-3)
a= 1
![Soma = \frac{-b}{a} Soma = \frac{-b}{a}](https://tex.z-dn.net/?f=Soma+%3D++%5Cfrac%7B-b%7D%7Ba%7D+)
![7 = \frac{-(2k-3)}{1} 7 = \frac{-(2k-3)}{1}](https://tex.z-dn.net/?f=7+%3D++%5Cfrac%7B-%282k-3%29%7D%7B1%7D+)
![7 = -2k + 3 7 = -2k + 3](https://tex.z-dn.net/?f=7+%3D+-2k+%2B+3)
![2k = 3-7 2k = 3-7](https://tex.z-dn.net/?f=2k+%3D+3-7)
![2k = -4 2k = -4](https://tex.z-dn.net/?f=2k+%3D+-4)
![k= \frac{-4}{2} k= \frac{-4}{2}](https://tex.z-dn.net/?f=k%3D++%5Cfrac%7B-4%7D%7B2%7D+)
![k = -2 k = -2](https://tex.z-dn.net/?f=k+%3D+-2)
a= 1
gustavocanabarro:
;)
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