Question

sabendo que a = 3/4 e b = -7/3, calcule:
a) a+b =
b) a-b =
c) b-a =

URGENTE

Answer 1

Resposta:

A.

$a+b=\\\frac{3}{4} +(-\frac{7}{3} ) = \\\frac{3}{4_{(\times3)}} -\frac{7}{3_{(\times4)}}} = \\\frac{9}{12}-\frac{28}{12} =\\\frac{9-28}{12} =\\\frac{-19}{12}$

B.

$a+b=\\\frac{3}{4} -(-\frac{7}{3} ) = \\\frac{3}{4_{(\times3)}} +\frac{7}{3_{(\times4)}}} = \\\frac{9}{12}+\frac{28}{12} =\\\frac{9+28}{12} =\\\frac{37}{12}$

C.

$b-a=\\-\frac{7}{3}-\frac{3}{4} = \\\frac{-7}{3_{(\times4)}} -\frac{3}{4_{(\times3)}}} = \\\frac{-28}{12}-\frac{9}{12} =\\\frac{-28-9}{12} =\\\frac{-37}{12}$