Question

Sabendo que ㏒2 = 0,301; ㏒3 = 0,477 e ㏒5 = 0,699 determine:
A, ㏒ 32=
B, ㏒ 27=
C, ㏒ 15

Answer 1

$a) \\ log{32} \\ log{ {2}^{5}} \\ 5 \times log{2} \\ 5 \times 0.301 \\ 1.505 \\ \\ b) \\ log{27} \\ log{ {3}^{3} } \\ 3 \times log{3} \\ 3 \times 0.477 \\ 1.431 \\ \\ c) \\ log{15} \\ log{(3 \times 5)} \\ log{3} + log{5} \\ 0.477 + 0.699 \\ 1.176$

Espero ter ajudado!