Question

Sabendo q log2=a e log3=b calcule a função de a e b:

a) Log1/4



b) Log 0,666....

Answer 1

a) $log\,(\frac{1}{4}) = log\,(\frac{1}{2^2}) = log\,2^{-2} = -2*log\,2 = -2*a = -2a$

b) $log\,0,6666... = log\,(\frac{6}{9}) = log\,6-log\,9 = log\,(2*3)-log\,(3*3) = \\ (log\,2+log\,3)-(log\,3+log\,3) = (a+a)-(a+b) = 2a-a-b = a-b$