Question

sabendo a função f:IR tal que f(x)=1+x²/x,calcule: A)f(2) B)f(-2) C)f¼ D)f(-¼)

Answer 1

f(x) = 1+x²/x
f(2) = 1+2²/2 = 1+4/2 = 1+2 = 3
f(-2) = 1+(-2)²/-2 = 1+4/-2 = 1-2 = -1
f(1/4) = 1+(1/4)²/1/4 = 1+1/16 / 1/4 = 1 + 1/16 . 4/1 = 1+4/16 = 1+1/4 = 5/4
f(-1/4) = 1+(-1/4)² / (-1/4) = 1+1/16 / -1/4 = 1 + 1/16 . (-4/1) = 1+(-4/16) = 1-1/4 = 4/4 - 1/4 = 3/4