sabendo a=2x-3 b=3x c=x+ 1 caucule 2.(a-b).c
Soluções para a tarefa
Respondido por
1
Olá!
![2\cdot (a-b)\cdot c=2\cdot[(2x-3)-(3x)]\cdot (x+1)=\\ \\ =
2\cdot (2x-3-3x)\cdot(x+1)=2\cdot(-x-3)\cdot(x+1)=\\ \\ =
(-2x-6)\cdot(x+1)=-2x^2-2x-6x-6=-2x^2-8x-6. 2\cdot (a-b)\cdot c=2\cdot[(2x-3)-(3x)]\cdot (x+1)=\\ \\ =
2\cdot (2x-3-3x)\cdot(x+1)=2\cdot(-x-3)\cdot(x+1)=\\ \\ =
(-2x-6)\cdot(x+1)=-2x^2-2x-6x-6=-2x^2-8x-6.](https://tex.z-dn.net/?f=2%5Ccdot+%28a-b%29%5Ccdot+c%3D2%5Ccdot%5B%282x-3%29-%283x%29%5D%5Ccdot+%28x%2B1%29%3D%5C%5C+%5C%5C+%3D+%0A2%5Ccdot+%282x-3-3x%29%5Ccdot%28x%2B1%29%3D2%5Ccdot%28-x-3%29%5Ccdot%28x%2B1%29%3D%5C%5C+%5C%5C+%3D+%0A%28-2x-6%29%5Ccdot%28x%2B1%29%3D-2x%5E2-2x-6x-6%3D-2x%5E2-8x-6.)
Bons estudos!
Bons estudos!
Perguntas interessantes
Sociologia,
11 meses atrás
Matemática,
11 meses atrás
Geografia,
11 meses atrás
Artes,
1 ano atrás
Matemática,
1 ano atrás