Question

Sabe-se que logm2 = a e log m3=b, calcule o valor de:

Logm 64/2,1 - log m60

Answer 1

Oi Barbara

logm(2) = a

log(2)/log(m) = a
log(2) = a*log(m)

log(3)/log(m) = b
log(3) = b*log(m) 

logm(7) = c
log(7)/log(m) = c
log(7) = c*log(m)

64/(2.1*60) = 32/63

log(32) = log(2^5) = 5log(2) = 5alog(m)

log(63) = log(9) + log(7) = 2log(3) + log(7) 

log(63) = 2b*log(m) + c*log(m)

log(32/63) = 5alog(m) - 2b*log(m) - c*log(m) 

log(32/63) = log(m)*(5a - 2b - c)