Question

s(x) = x2 – 13x + 42
me ajudem nessa​

Answer 1

Resposta:

Explicação passo-a-passo:

$x^{2}-13x+42=0\\\\\Delta=(b)^{2}-4(a)(c)=(-13)^{2}-4(1)(42)=169-(168)=1\\\\x^{'}=\frac{-(b)-\sqrt{\Delta}}{2(a)}=\frac{-(-13)-\sqrt{1}}{2(1)}=\frac{13-1}{2}=\frac{12}{2}=6\\\\x^{''}=\frac{-(b)+\sqrt{\Delta}}{2(a)}=\frac{-(-13)+\sqrt{1}}{2(1)}=\frac{13+1}{2}=\frac{14}{2}=7$