Química, perguntado por elenavitoria06, 4 meses atrás

S + 3/2 O2 = SO3


a) Qual o volume de S03, nas CNTP, formado na neação de 8g de enxofre?
b) Quantas moléculas de SO3 sao formadas na reação de 8g de oxigênio? ​

Soluções para a tarefa

Respondido por CyberKirito
1

\large\boxed{\begin{array}{l}\rm S+\dfrac{3}{2}O_2\longrightarrow SO_3\\\\\rm 2S+3O_2\longrightarrow 2SO_3\\\sf a)\\\rm64\,g\,de\,S\longrightarrow44,8\,L\,de\,SO_3\\\rm 8\,g\,de\,S\longrightarrow x\,L\,de\,SO_3\\\rm 64x=8\cdot44,8\\\rm x=\dfrac{\diagdown\!\!\!\!8\cdot44,8}{\diagdown\!\!\!\!\!\!64_8}\\\\\rm x=\dfrac{44,8}{8}\\\\\rm x=5,6\,L\,de\,SO_3\end{array}}

\large\boxed{\begin{array}{l}\sf b)\\\rm 2S+3O_2\longrightarrow 2SO_3\\\rm 96\,g\,de\,O_2\longrightarrow12,04\cdot10^{23}\,mol\acute eculas\,de\,SO_3\\\rm 8\,g\,de\,O_2\longrightarrow x\,mol\acute eculas\,de\,SO_3\\\rm 96x=8\cdot12,04\cdot10^{23}\\\rm x=\dfrac{\diagdown\!\!\!\!8\cdot12,04\cdot10^{23}}{\diagdown\!\!\!\!\!\!96}\\\\\rm x=\dfrac{12,04\cdot10^{23}}{12}\\\\\rm x\approxeq10^{23}\,mol\acute eculas\,de\,SO_3\end{array}}

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