Question

retangulo altura x+2 area 56m2 largura x+3

Answer 1

(x+2)(x+3) = 56
x² + 5x + 6 = 56
x² + 5x + 6 - 56 = 0
x² + 5x -50 = 0
(x+10)(x-5)=0
x+10 =0
x = -10
x-5 = 0
x= 5

x = 5

Answer 2

Olá!!!

Resolução!!!

A = b × h
= ( x + 3 ) ( x + 2 ) = 56
= x² + 2x + 3x + 6 = 56
= x² + 5x + 6 = 56
= x² + 5x + 6 - 56 = 0
= x² + 5x - 50 = 0

a = 1, b = 5, c = - 50

∆ = b² - 4ac
∆ = 5² - 4 • 1 • ( - 50 )
∆ = 25 + 200
∆ = 225

x = - b ± √∆ / 2a
x = - 5 ± √225 / 2 • 1
x = - 5 ± 15 / 2
x' = - 5 + 15 / 2 = 10/2 = 5
x" = - 5 - 15 / 2 = - 20/2 = - 10

R = 5

Espero ter ajudado!!!