Question

Resultado de (x+3)²=0?

Answer 1

(x + 3)² = 0
x² + 2 . x . 3 + 3² = 0
x² + 6x + 9 = 0

a = 1; b = 6; c = 9

x = [- b ± √(b² - 4ac)] / 2a
x = [- 6 ± √(6² - 4 . 1 . 9)] / 2 . 1
x = [- 6 ± √(36 - 36)] / 2
x = [- 6 ± √0] / 2
x = [- 6 ± 0] / 2
x' = [- 6 + 0] / 2 = -6 / 2 = -3
x'' = [- 6 - 0] / 2 = -6 / 2 = -3

S = {-3}

Espero ter ajudado. Valeu!

Answer 2

(x+3).(x+3)=0
faz distributiva vai ficar
x²+3x+3x+9=0
x²+6x+9=0
entao vc aplica baskara
Δ= b² - 4a.c
Δ= 6² - 4.1.9
Δ=36 - 36
Δ=0
x=(-b+-√Δ)/2
x=(-6+-√0)/2
x=-6/2
x=-3