Question

responder com calculo ate 22:30 pfv​

Answer 1

1) P= 3.10

P= 30 N

° Fat= 0,4.30

Fat= 12 N

2)

P = m . g

P= 10 . 10 = 100N

Fn = 100N

Fatk = Fn . Mk

Fatk = 100 . 0,6

Fatk = 60N

3) alternativa C

Encontrar a força de atrito cinético (Fatc):

m = 120 kg

a = 2 m/s^2

g = 10m/s^2

F = 600 N

Mc = ?

Fr = m . a

Fr = 120 . 2

(600 - Fatc) = 240

- Fatc = 240 - 600

- Fatc = -360 (-1)

Fatc = 360

Encontrando coeficiente de atrito cinético (Mc):

Fatc = 360 N

Fn = P = m.g = 120 . 10 = 1200 N

Mc = ?

Fatc = Fn . Mc

360 = 1200 . Mc

360 / 1200 = Mc

Mc = 0,3