Question

respondam essas duas questões!

Answer 1

1)

$A_T=6a^2\\ \\ 6a^2=1734\\ \\ a^2=\frac{1734}{6}\\ \\ a^2=289\\ \\ a=\sqrt{289}\\ \\ a=17 \ cm$

2)

$A_r=b.h\\ \\ 375=50.h\\ \\ h=\frac{375}{50}=7,5 \ m$