Question

Responda pra mim ce não reprovo com resolução rapido eu agradeço.(x+2)²+2(x-3)²+(x+4)(x-4)

Answer 1

$(x+2)^2=x^2+4x+4$

$2(x-3)^2=2(x^2-6x+9)=2x^2-12x+18$

$(x+4)(x-4)=x^2-16$

Assim:

$(x^2+4x+4)+(2x^2-12x+18)+(x^2-16)=4x^2-8x+6$

Answer 2

$(x+2)^2+2(x-3)^2+(x+4)(x-4)=\\\\(x)^2+2\cdot(x)\cdot(2)+(2)^2+2[(x)^2+2\cdot(x)\cdot(-3)+(-3)^2]+(x)^2-(4)^2=\\\\x^2+4x+4+2(x^2-6x+9)+x^2-16=\\\\x^2+4x+4+2x^2-12x+18+x^2-16=\\\\(x^2+2x^2+x^2)+(4x-12x)+(4+18-16)=\\\\\boxed{4x^2-8x+6}$