Question

Responda por favor. Log5.log4.log3(x-5)=0

Answer 1

log5(log4(log3x))=0
log4(log3x)=5^0
log4(log3x0=1
log3x=4^1 
log3x=4
x=3^4
que então 
x=81

Answer 2

Resolução:

$log5.log4.log3(x-5) \\ \\ log5.log4.log(3x-15)=0 \\ \\log5.log4.log(3x-15)=0. (\frac{1}{log5.log4} )\\ \\ \frac{log5.log4.log(3x-15)}{log5.log4} = \frac{0}{log5.log4} \\ \\ \log(3x-15)= 0 \\ \\ 3x-15= 10^{0} \\ \\ 3x-15=1 \\ \\ 3x=16 \\ \\ x= \frac{16}{3}$



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