Question

Responda por favor a questão desde já agradeço.

Answer 1

Calcule as frações e, se possível, simplifique o resultado.

a) $\dfrac{1}{10}+\dfrac{1}{10}$

$=\dfrac{1+7}{10}\\\\\\ =\dfrac{8}{10}\begin{array}{c}^{\div 2}\\^{\div 2} \end{array}\\\\\\=\dfrac{4}{5}$

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b) $\dfrac{5}{6}-\dfrac{1}{6}$

$=\dfrac{5-1}{6}\\\\\\ =\dfrac{4}{6}\begin{array}{c}^{\div 2}\\^{\div 2} \end{array}\\\\\\=\dfrac{2}{3}$

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c) $\dfrac{1}{10}+\dfrac{7}{10}-\dfrac{3}{10}$

$=\dfrac{1+7-3}{10}\\\\\\ =\dfrac{8-3}{10}\\\\\\ =\dfrac{5}{10}\begin{array}{c}^{\div 5}\\^{\div 5} \end{array}\\\\\\=\dfrac{1}{2}$

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d) $\dfrac{7}{15}-\dfrac{3}{15}-\dfrac{1}{15}$

$=\dfrac{7-3-1}{15}\\\\\\ =\dfrac{4-1}{15}\\\\\\ =\dfrac{3}{15}\begin{array}{c}^{\div 3}\\^{\div 3} \end{array}\\\\\\=\dfrac{1}{5}$

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e) $\dfrac{7}{20}+\dfrac{1}{20}+\dfrac{7}{20}$

$=\dfrac{7+1+7}{20}\\\\\\ =\dfrac{8+7}{20}\\\\\\ =\dfrac{15}{20}\begin{array}{c}^{\div 5}\\^{\div 5} \end{array}\\\\\\=\dfrac{3}{4}$

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f) $\dfrac{5}{18}+\dfrac{11}{18}-\dfrac{13}{18}$

$=\dfrac{5+11-13}{18}\\\\\\ =\dfrac{16-13}{18}\\\\\\ =\dfrac{3}{18}\begin{array}{c}^{\div 3}\\^{\div 3} \end{array}\\\\\\=\dfrac{1}{6}$

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g) $\dfrac{7}{6}+\dfrac{4}{6}-\dfrac{5}{6}+\dfrac{3}{6}-\dfrac{9}{6}$

$=\dfrac{7+4-5+3-9}{6}\\\\\\ =\dfrac{11-5+3-9}{6}\\\\\\ =\dfrac{6+3-9}{6}\\\\\\ =\dfrac{9-9}{6}\\\\\\ =\dfrac{0}{6}\\\\\\ =0$

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h) $\dfrac{1}{20}+\dfrac{3}{20}+\dfrac{11}{20}-\dfrac{7}{20}$

$=\dfrac{1+3+11-7}{20}\\\\\\ =\dfrac{4+11-7}{20}\\\\\\ =\dfrac{15-7}{20}\\\\\\ =\dfrac{8}{20}\begin{array}{c}^{\div 4}\\^{\div 4} \end{array}\\\\\\=\dfrac{2}{5}$


Bons estudos! :-)