Question

Responda essa ai pvfr

Answer 1

$\left(\dfrac{1}{2}\right)^3+\left(\dfrac{1}{4}\right)^2-2^{-3}+16^0=\dfrac{1^3}{2^3}+\dfrac{1^2}{4^2}-\dfrac{1}{2^3}+16^0=\dfrac{1}{8}+\dfrac{1}{16}-\dfrac{1}{8}+1=\dfrac{1}{16}+1=\dfrac{1}{16}+1\cdot \dfrac{16}{16}=\dfrac{1+16}{16}=\boxed{\dfrac{17}{16}}$