Question

Responda

c) 4x² + 8x + 3 = 0
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Answer 1

Resposta:

Explicação passo-a-passo:

$\displaystyle Aplicando~a~f\'{o}rmula~de~Bhaskara~para~4x^{2}+8x+3=0~~e~comparando~com~(a)x^{2}+(b)x+(c)=0,~determinamos~os~coeficientes:~\\a=4{;}~b=8~e~c=3\\\\C\'alculo~do~discriminante~(\Delta):&\\&~\Delta=(b)^{2}-4(a)(c)=(8)^{2}-4(4)(3)=64-(48)=16\\\\C\'alculo~das~raizes:&\\x^{'}=\frac{-(b)-\sqrt{\Delta}}{2(a)}=\frac{-(8)-\sqrt{16}}{2(4)}=\frac{-8-4}{8}=\frac{-12}{8}=-1,5\\\\x^{''}=\frac{-(b)+\sqrt{\Delta}}{2(a)}=\frac{-(8)+\sqrt{16}}{2(4)}=\frac{-8+4}{8}=\frac{-4}{8}=-0,5\\\\S=\{-1,5,~-0,5\}$

Answer 2

Resposta:

4x²+8x+3=

16x+8x+3=

24x+3=

27x