Question

responda


a) 3². √16=


b)√64:2³+1=


c)√81+5²-20=


d)√4. (2³+2²+2):7


e)7²:[(3³-3²-3):3+2]=

um zero pequeno qui

0

f)[√1.[√(13+12)-√(20-4)]: 1 0 ]=

uma quatro pequeno aqui

4

g)3+{3³.[3³-(√3²+√3 4 :3).3]:3²}=


h){5²-[√(2².4³:16)-2²].√625-5²}=

Answer 1

Resposta:

$a) \\ {3}^{2} \times \sqrt{16} = \\ 9 \times 4 \\ 36$

$b) \\ \ \sqrt{64} \div {2}^{3} +1= \\ 8 \div 8 + 1 = \\ 1 + 1 = 2$

$c) \\ \sqrt{81} + {5}^{2} - 20 = \\ 9 + 25 - 20 = \\ 14$

$d) \\ \sqrt{4} \times ( {2}^{3} + {2}^{2} + 2) \div 7 \\ 2 \times (8 + 4 + 2) \div 7 \\ 2 \times 14 \div 7 \\ 28 \div 7 \\ 4$