Question

respectivame x^2-4x+7=0

Answer 1

${x}^{2} - 4x + 7 = 0 \\ \\ \\ x = \sqrt{ \frac{ - ( - 4)± \sqrt{( - 4)^{2} - 4 \times 1 \times 7 } }{2 \times 1} } \\ \\ x = \sqrt{ \frac{4± \sqrt{16 - 28} }{2} } \\ \\ x = \sqrt{ \frac{4± \sqrt{ - 12} }{2} }$

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