Question

resolver x2-3x+2=0
preciso desta resposta ate amanhã 

Answer 1

$x^{2} -3+2=0 \Delta= b^{2} -4.a.c= \Delta= -3^{2} -4.1.2= \Delta=9-8=1  x^{1} =-+(-3) \sqrt{1} /2=3-1/2=2/2=1 x^{2} =-+(-3) \sqrt{1} /2=3+1/2=4/2=2$


S{1,2}

Answer 2

$x^2-3x+2=0$ 

a⇒ 1
b⇒-3
c ⇒ 2

$\Delta=b^2-4ac\\\Delta=(3)^2-4.1.2\\\Delta=9-8\\\Delta=1$

$x= \frac{-b\pm \sqrt{\Delta} }{2a}$

$x= \frac{3\pm1}{2}$

$x_1= \frac{3+1}{2} ~\to~ \frac{4}{2} ~\to~\boxed{x_1=2}$

$x_2= \frac{3-1}{2} ~\to~ \frac{2}{2} ~\to~\boxed{x_2=1}$

$S=\{2;1\}$