Question

resolver relações trigonométrica sen3x=1? alguém sabe? por favor ;)

Answer 1

$\text{sen}(3x)=1$

Temos que $\text{sen}(90^{\circ})=1$ e $\text{sen}(90^{\circ}+360^{\circ})=1$.

Lembrando que $360^{\circ}=2\pi~\text{rad}~~$ e $90^{\circ}=\dfrac{\pi}{2}~\text{rad}$, concluímos que:
 
$3x=\dfrac{\pi}{2}+2\pi\cdot k$

$x=\dfrac{\pi}{6}+\dfrac{2\pi\cdot k}{3}$, com $k\in\mathbb{N}$