Question

Resolver os sistemas pelo método da adição




x=3y
x+2y=10

Answer 1

$\left \{ {{x-3y=0\ \ \ \ \ \ \ \ \ \ } \atop {x+2y=10\ \ \times(-1)}} \right.\ \ \Rightarrow\ \ \left \{ {{x-3y=0\ \ } \atop {-x-2y=-10}} \right. \\\\ Somando:\\\\ \left+ \{ {{x-3y=0\ \ } \atop {-x-2y=-10}} \right.\\\\ 0x-5y=-10\\\\ Encontrando\ valor\ de\ y:\\\\ -5y=-10\\\\ y=\frac{-10}{-5}\\\\ \boxed{y=2}$

$Trocando\ o\ valor\ de\ \underline y\ em\ qualquer\ equa\c{c}\~ao\ inicial,\\ para\ encontrar\ valor\ de\ x:\\\\ x-3y=0\\\\ x-3(2)=0\\\\ x-6=0\\\\ \boxed{x=6}$


$==Prova\ real==\\\\ Equa\c{c}\~ao\ 1:\\\\ x=3y\\\\ (6)=3(2)\\\\ 6=6\\\\\\ Equa\c{c}\~ao\ 2:\\\\ x+2y=10\\\\ (6)+2(2)=10\\\\ 6+4=10\\\\ 10=10$

Bons estudos!