Question

Resolver o sistema:


x ∧ j = k


x.(4i-2j+k)=10

Answer 1

x= (a,b,c)
x^j = k
então 
(a,b,c)^(0,1,0) = (0,01)

a=i 
b=j
c=k

i ^J = k = a =(0,01) 
j^j = 0
k^j = -i = 
c=i
a=k
(c,0,a) = (0,0,1)
c=0
a=1


(a,b,c) (4-2+k)=10
(4a 2b+c)=10

4(0,0,1) = 4
4+2b=10
2b=10-4
b=-3

X= (a, b, c)
x = (1,-3,0)