Question

resolver o sistema de equaçao abaixo: 0,22(11-0,3)+4/7?

Answer 1

$<var>0,22(11-0,3)+\frac{4}{7}=\\ \frac{22}{100}(11-\frac{3}{10})+\frac{4}{7}=\\ \frac{22}{100}(\frac{110-3}{10})+\frac{4}{7}=\\ \frac{22}{100}.\frac{107}{10}+\frac{4}{7}=\\ \frac{2354}{1000}+\frac{4}{7}=\\ \frac{16478}{7000}+\frac{4000}{7000}=\\ \frac{20478}{1000}= 20,478</var>$