Question

resolver no conjunto IR a equacao √x+5=x-1

Answer 1

(√x+5)^2=(x-1)^2

x+5 -x^2 +2x -1 =0

-x^2 +3x +4 = 0.(-1)

x^2 -3x -4 = 0

b^2 -4ac

9 + 16

25

-b -+√delta /2a

3 -+ 5 /2

x' 8/2= 4

x'' -2/2 =-1

verificando

4=x

√4+5 = 4 - 1

3=3 (V)

-1=x

√-1+5 = -1-1

2=-2 (F)

S={4}