resolver logaritmo
log 5x base 5
madroots:
nao 5x
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Se for ![log_{5}(5x) log_{5}(5x)](https://tex.z-dn.net/?f=log_%7B5%7D%285x%29)
![log_{5}(5x) = log_{5}(5*x)\\log_{5}(5x)=log_{5}(5)+log_{5}(x)\\log_{5}(5x)=1+log_{5}(x) log_{5}(5x) = log_{5}(5*x)\\log_{5}(5x)=log_{5}(5)+log_{5}(x)\\log_{5}(5x)=1+log_{5}(x)](https://tex.z-dn.net/?f=log_%7B5%7D%285x%29+%3D+log_%7B5%7D%285%2Ax%29%5C%5Clog_%7B5%7D%285x%29%3Dlog_%7B5%7D%285%29%2Blog_%7B5%7D%28x%29%5C%5Clog_%7B5%7D%285x%29%3D1%2Blog_%7B5%7D%28x%29)
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Se for![log_{5}(5^{x}) log_{5}(5^{x})](https://tex.z-dn.net/?f=log_%7B5%7D%285%5E%7Bx%7D%29)
![log_{5}(5^{x})= x*log_{5}(5)\\log_{5}(5^{x})=x*1\\log_{5}(5^{x})=x log_{5}(5^{x})= x*log_{5}(5)\\log_{5}(5^{x})=x*1\\log_{5}(5^{x})=x](https://tex.z-dn.net/?f=log_%7B5%7D%285%5E%7Bx%7D%29%3D+x%2Alog_%7B5%7D%285%29%5C%5Clog_%7B5%7D%285%5E%7Bx%7D%29%3Dx%2A1%5C%5Clog_%7B5%7D%285%5E%7Bx%7D%29%3Dx)
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