Question

Resolver log de 8 na base 64.

Answer 1

Prezado.

$log_6_4 8=x \\ 64^x= 8 \\ (8^2)^x= 8 \\ 8 ^{2x} = 8^1 \\ 2x= 1 \\ \boxed{\boxed{x= \frac{1}{2} }}$