Question

resolver equaços experimental

Answer 1

Number 1

$3^x = \frac{1}{81} \\\\3^x = \frac{1}{3^4}\\\\3^x = 3^{-4}\\\\\boxed{x = -4 }$

Number 2

$2^{x+1} = 16\\\\2^{x+1} = 2^{4}\\\\x+1 = 4\\\\\boxed{x = 3}$

Number 3

$9^x = 27\\\\(3^2)^x = 3^{3}\\\\3^{2x} = 3^{3}\\\\2x = 3\\\\\boxed{x = \frac{3}{2} }$

Number 4

$3^{x^2-x} = 9\\\\3^{x^2-x} = 3^{2}\\\\x^2-x = 2\\\\x^2-x -2 = 0\\\\\Delta = (-1)^2-4*(1)(-2) = 1+8 = 9\\\\x = \frac{1\pm3}{2} \left \{ {{x'=2} \atop {x"=-1}} \right. \\\\S = \{-1,2\}$


* = multiplicação.

Espero ter ajudado. :))