Question

Resolver as seguintes Inequações:
a)3x + 1 > 2x − 14
b)8x − 16 + 3x + 3 > 6x − 6 + 12x
c) 2(x + 3) > 3(1 − x)
d) 3(1 − 2x) < 2(x + 1) + x − 7

Answer 1

Resposta:

a-) -15

b-) -1

c-) -3/5

d-) 8/9

Explicação passo-a-passo:

a)3x + 1 > 2x − 14

3x-2x > -14-1

x > -15

b)8x − 16 + 3x + 3 > 6x − 6 + 12x

8x+3x-6x-12x > -6+16-3

11x-18x > 16-9

-7x > 7 (-1)

7x < -7

x < -7/7

x < -1

c) 2(x + 3) > 3(1 − x)

2x+6 > 3-3x

2x+3x > 3-6

5x > -3

x > -3/5

d) 3(1 − 2x) < 2(x + 1) + x − 7

3-6x < 2x+2+x-7

-6x-2x-x < -3-7+2

-9x < -10+2

-9x < -8 (-1)

9x > 8

x > 8/9