Resolver as equações usando Bhaskara.
1) 3x²-27=0
2) x²-6x=0
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1) 3x²-27=0a=3 b=0 c=-27
Δ=b²-4acΔ=0²-4.3.-27Δ=324
x=-b±√Δ/2a
x'=-0+18/6x'=3
x"=-18/6x"=-3
S=[-3;3]
2) x²-6x=0a=1 b=-6 c=0
Δ=b²-4acΔ=-6²-4.1.0Δ=36
x=-b±√Δ/2a
x'=+6+6/2x'=12/2x'=6
x"=+6-6/2x"=0/2x"=0
S=[0;6]
Δ=b²-4acΔ=0²-4.3.-27Δ=324
x=-b±√Δ/2a
x'=-0+18/6x'=3
x"=-18/6x"=-3
S=[-3;3]
2) x²-6x=0a=1 b=-6 c=0
Δ=b²-4acΔ=-6²-4.1.0Δ=36
x=-b±√Δ/2a
x'=+6+6/2x'=12/2x'=6
x"=+6-6/2x"=0/2x"=0
S=[0;6]
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