Resolver as equações exponencial
.
A) 3 = 1/729
C) (9/16)=(4/3)
D)(2/3)=1
F) 5 2x2=5
H)9*=(1/9)
OLHEM NA FOTO!!!! A, C, D, F, H
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Soluções para a tarefa
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a) 3^x = 1/729
3^x = 1/3^6
3^x = 3^-6
x = -6
c) (9/16)^(2x - 1) = (4/3)^(-x + 1)
(9/16)^(2x - 1) = (3/4)^(x - 1)
(3²/4²)^(2x - 1) = (3/4)^(x - 1)
(3/4)^(4x - 2) = (3/4)^(x - 1)
4x - 2 = x - 1
4x - x = -1 + 2
3x = 1
x = 1/3
d) (2/3)^(3x +1) = 1
(2/3)^3x + 1) = (2/3)^0
3x + 1 = 0
3x = -1
x = -1/3
f) 5^(3 x - 2) = 5
3x - 2 = 1
3x = 1 + 2
3x = 3
x = 3/3
x = 1
h) 9^(2x + 1) = (1/9)^x
(9)^(2x + 1) =9^-x
2x + 1 = -x
2x + x = -1
3x = -1/3
Espero ter ajudado.
3^x = 1/3^6
3^x = 3^-6
x = -6
c) (9/16)^(2x - 1) = (4/3)^(-x + 1)
(9/16)^(2x - 1) = (3/4)^(x - 1)
(3²/4²)^(2x - 1) = (3/4)^(x - 1)
(3/4)^(4x - 2) = (3/4)^(x - 1)
4x - 2 = x - 1
4x - x = -1 + 2
3x = 1
x = 1/3
d) (2/3)^(3x +1) = 1
(2/3)^3x + 1) = (2/3)^0
3x + 1 = 0
3x = -1
x = -1/3
f) 5^(3 x - 2) = 5
3x - 2 = 1
3x = 1 + 2
3x = 3
x = 3/3
x = 1
h) 9^(2x + 1) = (1/9)^x
(9)^(2x + 1) =9^-x
2x + 1 = -x
2x + x = -1
3x = -1/3
Espero ter ajudado.
lorenaxz:
O q significa ^?
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