Question

¨resolver as equações do 2º grau
x²-4x=3x+8

Answer 1

$x^2-4x=3x+8\\x^2-4x-3x-8=0\\x^2-7x-8=0$

$\Delta=(-7)^2-4.1.(-8)\\\Delta=49+32\\\Delta=81$

$x= \frac{7\pm9}{2}$

$x'=-1$

$x''=8$