Question

resolver as equações do 2 grau​

Answer 1

a) A = 49 B = 0 C = -1

Δ = B² - 4.A.C

Δ = 0² - 4.49.(-1)

Δ = 0 + 196

Δ = 196

X = -B +- √Δ / 2.A

X| = X|| = 14 / 98

b) A = 4 B = -12 C = 0

Δ = B² - 4.A.C

Δ = (-12)² - 4.4.0

Δ = 144 + 0

Δ = 144

X = -B +- √Δ / 2.A

X = -(-12) +- √144 / 2.4

X = 12 +- 12 / 8

X| = 12 + 12 / 8

X| = 24 / 8

X| = 3

X|| = 12 - 12 / 8

X|| = 0 / 8

X|| = 0

c) A = 1 B = -6 C = 8

Δ = B² - 4.A.C

Δ = (-6)² - 4.1.8

Δ = 36 - 32

Δ = 4

X = -B +- √Δ / 2.A

X = -(-6) +- √4 / 2.1

X = 6 +- 2 / 2

X| = 6 + 2 / 2

X| = 8 / 2

X| = 4

X|| = 6 - 2 / 2

X|| = 4 / 2

X|| = 2

d) A = 1 B = -2 C = 3

Δ = B² - 4.A.C

Δ = (-2)² - 4.1.3

Δ = 4 - 12

Δ = -8

Não existem raízes reais.