Question

Resolver a equação em C: 2x(ao quadrado) –6x+7=0

Answer 1

2x² - 6x + 7 = 0

Δ = b² −4ac

Δ = (−6)² −4⋅(2)⋅(7)

Δ = 36 − 56

Δ = −20

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$x = \dfrac{-b \pm \sqrt{\Delta}}{2*a}\\ \\ \\ x = \dfrac{-(-6) \pm \sqrt{-20}}{2*2}\\ \\ \\ x = \dfrac{6 \pm \sqrt{20} . i}{4}\\ \\ \\ x = \dfrac{6 \pm 2\sqrt{5} . i}{4}\\ \\ \\ x' = \dfrac{3 - 2\sqrt{5} . i}{2}\\ \\ \\ x'' = \dfrac{3 + 2\sqrt{5} . i}{2}$

S = {$\dfrac{3 - 2\sqrt{5} . i}{2}, \ \ \ \dfrac{3 + 2\sqrt{5} . i}{2}$}