Question

Resolvendo em R a equação log3(2x + 3) = 2 obtemos:

Answer 1

$\large\boxed{\begin{array}{l}\sf C. E: ~2x+3>0\\\sf2x>-3\\\sf x>-\dfrac{3}{2}\\\underline{\rm soluc_{\!\!,}\tilde ao\!:}\\\sf \ell og_3(2x+3)=2\\\sf 2x+3=3^2\\\sf 2x+3=9\\\sf 2x=9-3\\\sf 2x=6\\\sf x=\dfrac{6}{2}\\\sf x=3\end{array}}$