Question

resolvendo a equaçao literal x²+2a.x+a²=0 obtemos:

Answer 1

$x^2+2ax+a^2=0\longrightarrow(x+a)(x+a)=0\longrightarrow(x+a)^2=0\longrightarrow\\\\x+a=\sqrt0\longrightarrow{x}+a=0\longrightarrow\boxed{{x}=-a}$