Question

Resolvendo a equação exponencial abaixo, obtemos:

Answer 1

(2)^(3x – 1) . (2)^[2 . (2x + 3)] = (2)^[3 . (3 – x)]

(2)^(3x – 1) . (2)^(4x + 6) = (2)^ (9 – 3x)

(2)^(3x – 1 + 4x + 6) = (2)^ (9 – 3x)

Cancelar as bases e igualar os expoentes.

3x – 1 + 4x + 6 = 9 – 3x

7x + 5 = 9 – 3x

7x + 3x = 9 – 5

10x = 4

x = 4/10

x = 2/5

 

Resposta: x = 2/5

Bons estudos!