Question

resolvendo a equação 5 tg2 x-5=0, sabendo que 0° < OU = X < OU = 360° obtemos:

A) V= {45°;225°}
B) V= {30°;150°;210°;330°}
C) V= {135°;315°}
D) V= {60°;240°}
E) V= {45°;135°;225°;315°}

Answer 1

5tg²x -5 = 0
5tg²x = 5
tg²x = 1
tgx = ± 1

tgx=+1:
x'=45° , x"=180+45=225°

tgx=-1
x"'= 180-45=135° , x""=360-45=315°

E) V= {45°;135°;225°;315°}