Question

Resolve este sistema
(x-2) (2-4x) =0

Answer 1

Resposta:

$(x - 2)(2 - 4x) = 0 \\ 2x - 4 {x}^{2} - 4 + 8x = 0 \\ - 4 {x}^{2} + 10x - 4 = 0 \\ - 2 {x}^{2} + 5x - 2 = 0 \\ \\ = {b}^{2} - 4ac \\ ( {5}^{2} ) - 4( - 2)( - 2) = \\ 25 - 16 = 9 \\ \\ x = \frac{ - b + - \sqrt{9} }{2a} = \frac{ - 5 + - 3}{2 \times ( - 2)} = \frac{5 + - 3}{ - 4} \\ x = \frac{5 + 3}{ - 4} = \frac{8}{ - 4} = - 2 \\ x = \frac{5 - 3}{ - 4} = \frac{2}{ - 4} = - \frac{1}{2}$