Matemática, perguntado por kimberllyS, 6 meses atrás

Resolve as seguintes equações: e pare na equação.
a) 6x + 2x = 5 + x
b) x (2x + 3) = 1
c) x (x + 3) + 2x = 6
d) x +( x + 1)² = 3
e) x² =2(4x)
f) 2 (x²-1)= 3x
g) 4 (x² + x) = 1x²
h) x 2x + 3) = 1

Soluções para a tarefa

Respondido por Eduardo44
0

a)6x+2x = 5+x

  8x-x = 5

  7x = 5

  x = 5/7

b)x(2x+3) = 1

  2x²+3x-1 = 0

  Δ = b²-4.a.c

  Δ = 3²-4.2.(-1)

  Δ = 9+8

  Δ = 17

 

  x = -b±√Δ/2.a

  x = -3±√17/2.2

  x = -3 ±√17/4

  x' = -3+√17/4

  x" = -3-√17/4

c)x(x+3)+2x = 6

  x²+3x+2x = 6

  x²+5x-6 = 0

  Δ = b²-4.a.c

  Δ = 5²-4.1.(-6)

  Δ = 25+24

  Δ = 49

  x = -b±√Δ/2.a

  x = -5±√49/2.1

  x = -5±7/2

  x'= -5+7/2 = 2/2 = 1

  x"= -5-7/2 = -12/2 = -6

d)x+(x+1)² = 3

  x+(x+1).(x+1) = 3

  x+ x²+x+x+1 = 3

  x²+3x+1-3 = 0

  x²+3x-2 = 0

  Δ = b²-4.a.c

  Δ = 3²-4.1.(-2)

  Δ = 9+8

  Δ = 17

 

  x = -b±√Δ/2.a

  x = -3±√17/2.1

  x = -3 ±√17/2

  x' = -3+√17/2

  x" = -3-√17/2

e)x² = 2(4x)

  x² = 8x

  x²-8x = 0

  Δ = b²-4.a.c

  Δ = (-8)²-4.1.0

  Δ = 64

 

  x = -b±√Δ/2.a

  x = -(-8)±√64/2.1

  x = 8±8/2

  x' = 8+8/2 = 16/2 = 8

  x" = 8-8/2 = 0/2 = 0

f)2(x²-1) = 3x

 2x²-2 = 3x

 2x²-3x-2 = 0

 Δ = b²-4.a.c

 Δ = (-3)²-4.2.(-2)

 Δ = 9+16

 Δ = 25

 

 x = -b±√Δ/2.a

 x = -(-3)±√25/2.2

 x = 3±5/4

 x' = 3+5/4 = 8/4 = 2

 x" = 3-5/4 = -2/4 = -1/2

g)4(x²+x) = x²

  4x²+4x-x² = 0

  3x²+4x = 0

  Δ = b²-4.a.c

  Δ = 4²-4.3.0

  Δ = 16

  x = -b±√Δ/2.a

  x = -4±√16/2.3

  x = -4±4/6

  x' = -4+4/6 = 0/6 = 0

  x" = -4-4/6 = -8/6 = -4/3

h)x(2x+3) = 1

  2x²+3x-1 = 0

  Δ = b²-4.a.c

  Δ = 3²-4.2.(-1)

  Δ = 9+8

  Δ = 17

  x = -b±√Δ/2.a

  x = -3±√17/2.2

  x = -3 ±√17/4

  x' = -3+√17/4

  x" = -3-√17/4

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