Question

resolvam pra mim porfavo 6^√ 7 . 4^√ 2 = (obs: 6^ indica indice 6 e 4^ indica índice 4)
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Answer 1

Resposta:

$\sqrt[6]{7} \times \sqrt[4]{2} = \\ \sqrt[6 \times 2]{ {7}^{ 1\times 2} } \times \sqrt[4 \times 3]{ {2}^{1 \times 3} } = \\ \sqrt[12]{49} \times \sqrt[12]{8} \\ \sqrt[12]{49 \times 8} \\ \sqrt[12]{392}$