Question

resolvam para mim,pfvvvv

Answer 1

$( \frac{3}{4}ab^2- \frac{4}{3}a^2b)+( \frac{5}{8}ab^2- \frac{5}{6}a^2b)=$

mmc(4,3,8,6) = 24

$\frac{18}{24}ab^2- \frac{32}{24}a^2b+ \frac{15}{24}ab^2- \frac{20}{24}a^2b=$

$\frac{33}{24}ab^2- \frac{52}{24}a^2b=$  simplificando:

$\frac{11}{8}ab^2- \frac{13}{6}a^2b$ <--- opção c