Question

Resolvam esse Log, por favor!
1/64㏒ na base 2

Answer 1

Resolução da questão, veja:


$log_{2}^{\dfrac{1}{64}}} = x\\\\\\\\\\ 2^{x} = \dfrac{1}{2^{6}}\\\\\\\ 2^{x} = 2^{-6}\\\\\\ \large\boxed{\boxed{\boxed{\boxed{\boxed{ x = -6.}}}}}}}}}$

Espero que te ajude :).

Answer 2

Olá!!

Outra...

$\\ \mathsf{\log_2 \frac{1}{64} =} \\\\ \mathsf{\log_2 \frac{1}{2^6} =} \\\\ \mathsf{\log_2 2^{- 6} =} \\\\ \mathsf{- 6 \cdot \log_2 2 =} \\\\ \mathsf{- 6 \cdot 1 =} \\\\ \boxed{\mathsf{- 6}}$