Question

resolvam essa equação exponencial

Answer 1

$2^{4x+1}\cdot 8^{(-x+3)}=\dfrac{1}{16}\\\\\Leftrightarrow\\\\2^{4x+1}\cdot2^{(-3x+9)}=2^{-4}\\\\\Leftrightarrow\\\\2^{x+10}=2^{-4}~\Longrightarrow~x+10=-4~\Leftrightarrow~x=-14$