Question

resolva  x4-13x2+36=0

Answer 1

$x^4 - 13x^2 + 36 = 0$

$(x + 2)(x^3 - 2x^2 - 9x + 18) \\ \\ (x + 2)*(x +3)(x^2 - 5x + 6) \\ \\ \\ (x + 2)*(x +3)*(x - 3)*(x - 2)$

Raízes:

x + 2 = 0   => x = -2

x + 3 = 0    => x = -3

x - 3 = 0    => x = 3

x - 2 = 0    => x = 2

S ={-2, -3, 3, 2}