Resolva : x2+11x+28 Formula de Bhaskara
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x² +11x +28
Δ= b² -4ac
Δ= 11² -4.1.28
Δ= 121 - 112
Δ= 9
x= -b +/- √Δ / 2a
x= -11 +/- √9 / 2.1
x'= -11 +3 / 2
x'= -8/2
x'= -4
x''= -11 -3 /2
x''= -14 /2
x''= -8
Bons estudos!
Δ= b² -4ac
Δ= 11² -4.1.28
Δ= 121 - 112
Δ= 9
x= -b +/- √Δ / 2a
x= -11 +/- √9 / 2.1
x'= -11 +3 / 2
x'= -8/2
x'= -4
x''= -11 -3 /2
x''= -14 /2
x''= -8
Bons estudos!
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